QUIZ 3-ATOM (SPECTRAL SERIES)

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1. The longest wavelength of balmer series is

656.3 nm

723.1 nm

670.1 nm

650.2 nm

2. If an electron is in 4th energy level then calculate the maximum number of probable spectral lines can be emitted by the atom.

3. The shortest wavelength of Balmer series will be

330.7 nm

275.6 nm

364.6 nm

350.8 nm

4. Formula to calculate the frequency of emitted photon during transition from higher energy level (n_i) to lower energy level (n_f)

\(v=Rc[{1\over n_f^2}-{1\over n_i^2}]\)

\(v=R[{1\over n_f^2}-{1\over n_i^2}]\)

\(v=Rc[{1\over n_i^2}-{1\over n_f^2}]\)

\(v=R[{1\over n_i^2}-{1\over n_f^2}]\)

5. H-alpha series is obtained in line spectrum of hydrogen atom

When electron jumps from fourth energy level to second energy level

When electron jumps from third energy level to first energy level

When electron jumps from fourth energy level to first energy level

When electron jumps from third energy level to second energy level

6. Name the spectral series in hydrogen spectrum which gives ultra violet radiations

Lyman

Balmer

Brackett

Paschen

7. Limitations of Bohr's model are

It is applicable to hydrogen like atoms only having only one electron.

It does not explain why the orbits are circular while elliptical orbits are also possible.

Not able to account the intensity variations in line spectrum.

All of the above.

8. Approximate value of reciprocal of Rydberg constant (1/R) is

911.57 A^o

911.60 A^o

911.8 A^o

912 A^o

9. Formula to calculate wavelength of emitted radiation when electron jump from higher level (n_i) to lower energy level (n_f)

\(\lambda=Rc[{1\over n_i^2}-{1\over n_f^2}]\)

\(\lambda=R[{1\over n_f^2}-{1\over n_i^2}]\)

\({1\over\lambda}=R[{1\over n_f^2}-{1\over n_i^2}]\)

\({1\over\lambda}=R[{1\over n_i^2}-{1\over n_f^2}]\)

10. Value of Rydberg constant (R) is

10.97 x 10⁷ m^-1

1.097 x 10⁷ m^-1

0.1097 x 10⁷ m^-1

1.097 x 10^-7 m^-1

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