1. Wavelength\((\lambda)\) of matter wave having momentum (p)  and mass(m) is given by

2. Formula of wavelength of an electron accelerated by a potential difference of V volt

3. First experimental proof to confirm the wave nature of material particle (electron).

4. Which formula to calculate wavelength of a particle is wrong( here symbols have their ususal meaning)

5. If the potential difference used to accelerate electrons is doubled, by what factor does the de-Broglie wavelength associated with the electrons change?

 

6. An electron and proton have same momentum. What will be the ratio of their De Broglie wavelength?(mass of electron=9.1 x10-31kg, mass of proton=1.6 x 10-27kg, plancks constant h= 6.6 x 10-34 JS)

7. A proton and an electron have same velocity. Which one has greater de-Broglie wavelength ?

8. Graph between wavelength of an electron and \(1\over\sqrt{V} \) is  (here V is accelerating potential)

9. Proton (P) and α-particles are accelerated through the same potential. Find the ratio of the de Broglie wavelengths of proton to the alpha particle.(Given m\(\alpha\)=4mp  and q\(\alpha\)=2qp)

 

10. Proton (P) and α-particles are having same kinetic energy. Find the ratio of the de Broglie wavelengths of proton to the alpha particle.(Given m\(\alpha\)=4mp  and q\(\alpha\)=2qp)

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